--%>

Explain the polymers and its types.

Polymers are the chief products of modern chemical industry which form the backbone of present society. Daily life without the discovery and varied applications of polymers would not have been easier and colourful. The materials made of polymers find multifarious uses and applications in all walks of our life. They have influenced our day to day life to such an extent that it is impossible to get through the day without using a material based on polymers. Common examples of these include plastic dishes, cups, non-stick. Pans, automobile tyres and seat covers, plastic bags, rain coats, plastic pipes and fitting radio, TV and computer cabinets; wide range of synthetic fibres for clothing, synthetic glues, flooring materials and materials for biomedical and surgical operations. 

Word polymer means "many parts" (Greek: poly means many and merors means parts). A polymer is a compound of high molecular mass created by the mixture of large number of small molecules. The small molecules which comprise the repeating units in a polymer are known as monomer units. The process by which the monomers are transformed into polymer is called polymerization. For example, polyethylene is a polymer which is obtained by the polymerization of ethylene. The ethylene molecules are referred to as monomer units.
1000_Polymers.png 
As polymers are single and giant molecules, i.e. big size molecules, they are also known as macromolecules.

Homopolymers and copolymers

Polymers are divided into two broad categories depending upon the nature of the repeating structural units. These are homopolymers and co-polymers.

The polymer formed from one kind of monomer is called homopolymers while polymer formed from more than one kind of monomer units is called copolymer or mixed polymer. For example, polyethylene is an example of homopolymers whereas Buna-S rubber which is formed from 1, 3-butadiene (CH2 = CH - CH = CH2) and styrene (C6H5CH = CH2) is an example of copolymer. 

 

 

 

   Related Questions in Chemistry

  • Q : How haloalkanes are prepared from

    This is the common method for preparing haloalkanes in laboratory. Alcohols can be converted to haloalkanes by substitution of - OH group with a halogen atom. Different reagents can be used to get haloa

  • Q : Vapour pressure of the pure hydrocarbons

    Give me answer of this question. A solution has a 1 : 4 mole ratio of pentane to hexane. The vapour pressure of the pure hydrocarbons at 20°C are 440 mmHg for pentane and 120 mmHg for hexane. The mole fraction of pentane in the vapour phase would be: (a) 0.549 (b)

  • Q : Problem on equilibrium constant Ethanol

    Ethanol is manufactured from carbon monoxide and hydrogen at 600 K and 20 bars according to the reaction2 C0(g) + 4 H2(g) ↔ C2H5OH(g) + H2O (g)The feed stream contains 60 mol% H2, 20 m

  • Q : Surface Tension Vapour Pressure The

    The vapor pressure of small liquid drops depends on the drop size. Although the surface properties of a liquid are different from those of the bulk liquid, the special surface properties can be ignored except in a few situations. One is the case in which a liquid is dispersed into fine dr

  • Q : Units of Measurement Unit of

    Unit of measurement- These are also some systems for units:      (1) C.G.S.

  • Q : Chem Explain how dissolving the Group

    Explain how dissolving the Group IV carbonate precipitate with 6M CH3COOH, followed by the addition of extra acetic acid.

  • Q : Base parachloroaniline is strong base

    parachloroaniline is strong base than paranitroaniline

  • Q : Colligative property associated question

    Give me answer of this question. Which of the following is not a colligative property : (a)Optical activity (b)Elevation in boiling point (c)Osmotic pressure (d)Lowering of vapour pressure

  • Q : What are the various types of drugs

    Drugs are broadly classified into following types depending on the purpose for which they are used. 1. Antipyretics

  • Q : Problem based on molarity Select the

    Select the right answer of the question. If 18 gm of glucose (C6H12O6) is present in 1000 gm of an aqueous solution of glucose, it is said to be: (a)1 molal (b)1.1 molal (c)0.5 molal (d)0.1 molal