--%>

Explain the polymers and its types.

Polymers are the chief products of modern chemical industry which form the backbone of present society. Daily life without the discovery and varied applications of polymers would not have been easier and colourful. The materials made of polymers find multifarious uses and applications in all walks of our life. They have influenced our day to day life to such an extent that it is impossible to get through the day without using a material based on polymers. Common examples of these include plastic dishes, cups, non-stick. Pans, automobile tyres and seat covers, plastic bags, rain coats, plastic pipes and fitting radio, TV and computer cabinets; wide range of synthetic fibres for clothing, synthetic glues, flooring materials and materials for biomedical and surgical operations. 

Word polymer means "many parts" (Greek: poly means many and merors means parts). A polymer is a compound of high molecular mass created by the mixture of large number of small molecules. The small molecules which comprise the repeating units in a polymer are known as monomer units. The process by which the monomers are transformed into polymer is called polymerization. For example, polyethylene is a polymer which is obtained by the polymerization of ethylene. The ethylene molecules are referred to as monomer units.
1000_Polymers.png 
As polymers are single and giant molecules, i.e. big size molecules, they are also known as macromolecules.

Homopolymers and copolymers

Polymers are divided into two broad categories depending upon the nature of the repeating structural units. These are homopolymers and co-polymers.

The polymer formed from one kind of monomer is called homopolymers while polymer formed from more than one kind of monomer units is called copolymer or mixed polymer. For example, polyethylene is an example of homopolymers whereas Buna-S rubber which is formed from 1, 3-butadiene (CH2 = CH - CH = CH2) and styrene (C6H5CH = CH2) is an example of copolymer. 

 

 

 

   Related Questions in Chemistry

  • Q : Thermodynamics 1 Lab Report I already

    I already did Materials and Methods section. I uploaded it with the instructions. Also, make sure to see Concept Questions and Thinking Ahead in the instructions that I uploaded. deadline is tomorow at 8 am

  • Q : Describe the properties of the

    Briefly describe the properties of the carbohydrates?

  • Q : Concentration of an aqueous solution

    Give me answer of this question. The concentration of an aqueous solution of 0.01M CH3OH solution is very nearly equal to which of the following : (a) 0.01%CH3OH (b) 0.1%CH3OH (c) xCH3OH= 0.01 (d) 0.99MH2O (

  • Q : Non-ideal Gases Fugacity The fugacity

    The fugacity is a pressure like quantity that is used to treat the free energy of nonideal gases.Now we begin the steps that allow us to relate free energy changes to the equilibrium constant of real, nonideal gases. The thermodynamic reaction 

  • Q : Molar mass of solute The boiling point

    The boiling point of benzene is 353.23 K. If 1.80 gm of a non-volatile solute was dissolved in 90 gm of benzene, the boiling point is increased to 354.11 K. Then the molar mass of the solute is: (a) 5.8g mol-1  (b)

  • Q : Problem based on mole concept Choose

    Choose the right answer from following. An aqueous solution of glucose is 10% in strength. The volume in which mole of it is dissolved will be : (a) 18 litre (b) 9 litre (c) 0.9 litre (d) 1.8 litre

  • Q : Problem based on molarity Select the

    Select the right answer of the question. If 18 gm of glucose (C6H12O6) is present in 1000 gm of an aqueous solution of glucose, it is said to be: (a)1 molal (b)1.1 molal (c)0.5 molal (d)0.1 molal

  • Q : What is covalent radii? Explain its

    Average covalent radii can be assigned on the basis of molecular structures. The accumulation of structural data by spectroscopic studies and both electron and x-ray diffraction studies allows one to investigate the possibili

  • Q : Strength of the Hydrochloric acid

    Provide solution of this question. 1.0 gm of pure calcium carbonate was found to need 50 ml of dilute HCL for complete reaction. The strength of the HCL solution is specified by : (a) 4 N (b) 2 N (c) 0.4 N (d) 0.2 N

  • Q : What do you mean by the term medicine

    What do you mean by the term medicine dropper? Explain briefly?