--%>

Explain Solid Compound Formation.

In some two component, solid liquid systems, a solid compound forms.

In systems in which the components have an interaction for such other, a solid state compound of the two compounds of the two components can form.

Formic acid and formaide form a solid state, one-to-one compound. The effect on the freezing point diagram is shown in fig. 1, such diagrams are understandable on the basis of the discussion of the diagrammatic problems. Each half of the fig. corresponds to the simple eutectic diagrams treated there.

Solutions which on cooling reach line NM or RW of fig. give rise to solid formaide, respectively. Solutions which on cooling reach line PN or PQ give rise to a solid which is a compound containing equimolar amounts of formic acid, and at point N the solution is in equilibrium with the new compound and formaide. Points and Q represent two eutectics that generally have different temperatures.

Again, as in the preceding section, the initial slopes of the lines at M, P and R can be interpreted in terms of the enthalpy of fusion and the freezing point of the substance that separates out as a solid near these points. Likewise, the curves can be interpreted in terms of the solubility of these components and can be compared with the ideal solution expectations given by the above equation.

Compound formation in the solid state is frequently encountered with hydrates, the formation of hydrated compounds of sulphuric acid in the solid state. Again, such diagrams are easily understood as a series of simple eutectic diagrams side by side.

A complication does occur when a solid compound does not have sufficient stability to persist up to the temperature at which it would melt. In such cases the unstable solid breaks down into a solution, and the solid state of one or the other of the two components. This is illustrated by the system calcium fluoride calcium chloride, as shown in the fig. the decomposition of such a solid is referred to as a peritectic reaction or an incongruent melting. Thus the equimolar crystal: CaF2. CaCl2 of fig. breaks down at 737 degree C into a solution of composition B and solid CaF2. The dashed line shows how the diagram might have looked if the compound had survived to a real or congruent melting point. This line is helpful for visualizing the phase behavior but has, of course, no real significance.

Miscible solids: brief mention can be made, particularly in view of their importance as alloys, of system forming only one solid phase which is a solid solution. Such behavior is a result of complete mutual solubility of the solid phases in each other affects the phase diagram of a system that shows a simple eutectic. Such a partial solubility frequently occurs when the atoms of one component are small and can fit into the interstices of the lattice of the major component. In this way an interstitial alloy is formed. The carbon atoms in a carbon containing alloy are usually so accommodated.

Complete solubility of two solid phases usually results when the atoms of the two components are about the same size and can substitute for each other in the lattice to form a substitutional alloy. The system of copper and nickel shows this behavior. The upper of the two curves shows the temperature at which solutions of various compositions start to freeze. The lower curve gives the comparison of the solid which separates out at that freezing point. In this system the solid is always richer melting component than the solution from which it separates. The alloy consisting of 60 percent copper and 40 percent nickel is known as constantan.  

   Related Questions in Chemistry

  • Q : Utilization of glacial acetic acid What

    What is the utilization of glacial acetic acid? Briefly describe the uses.

  • Q : Ionic radius of chloride ion The edge

    The edge length of the unit cell of Nacl crystal lattice is 552 pm. If ionic radius of sodium ion is 95. What is the ionic radius of chloride ion:(a) 190 pm  (b) 368 pm  (c) 181 pm  (d) 276 pm     <

  • Q : Question related to molarity Help me to

    Help me to go through this problem. Molarity of a solution containing 1g NaOH in 250ml of solution: (a) 0.1M (b) 1M (c) 0.01M (d) 0.001M

  • Q : Molarity of Barium hydroxide 25 ml of a

    25 ml of a solution of barium hydroxide on titration with 0.1 molar solution of the hydrochloric acid provide a litre value of 35 ml. The molarity of barium hydroxide solution will be: (i) 0.07 (ii) 0.14 (iii) 0.28 (iv) 0.35

  • Q : Strength of any solution Give me answer

    Give me answer of this question. A solution contains 1.2046 x 1024 hydrochloric acid molecules in one dm3 of the solution. The strength of the solution is: (a) 6 N (b) 2 N (c) 4 N (d) 8 N

  • Q : Calculating total vapour pressure

    Select the right answer of the question. The vapour pressure of two liquids P and Q are 80 and 600 torr, respectively. The total vapour pressure of solution obtained by mixing 3 mole of P and 2 mole of Q would be: (a) 140 torr (b) 20 torr (c) 68 torr (d) 72 torr

  • Q : Molality of glucose Help me to go

    Help me to go through this problem. Molecular weight of glucose is 180. A solution of glucose which contains 18 gms per litre is : (a) 2 molal (b) 1 molal (c) 0.1 molal (d)18 molal

  • Q : Explain the process of coagulation of

    Presence of small concentrations of appropriate electrolyte is necessary to stabilize the colloidal solutions. However, if the electrolytes are present in higher concentration, then the ions of the electrolyte neutralize the charge on the colloidal particles may unite

  • Q : Moles of chloride ion Select the right

    Select the right answer of the question. A solution of CaCl2 is 0.5 mol litre , then the moles of chloride ion in 500ml will be : (a) 0.25 (b) 0.50 (c) 0.75 (d)1.00

  • Q : What do you mean by the term alum What

    What do you mean by the term alum? Also illustrate its uses?