--%>

Explain Ionic Bond with examples.

The bonding in ionic molecules can be described with a coulombic attractive term.

For some diatomic molecules we take quite a different approach from that used in preceding sections to describe the bonding. Ionic bonds are interpreted in terms of the coulombic attraction between ions. Since the electronic details of these ions are not dealt with the approach does not require quantum mechanical calculations. The treatment is easier but, as you will see, less satisfying than those in which a complete quantum mechanical description is set up and, with various recognized simplifications, solved.

Let us consider, to be specific, the NaCl molecule. The molecule exists in the high temperature vapour, and its bonding energy and equilibrium bond length and some features of its energy versus internuclear distance curve are known. These are shown by the solid curve of the products of dissociation of an NaCl molecule are the gas phase Na and Cl atoms.

Now let us attempt to develop an energy intermolecular distance curve by using the internuclear model. The energy required converting Na atoms to Na+ ions and Cl atoms to Cl- ions, all in the gas state, can be calculated from ionization:

Na 2118_First order reactions1.png Na = + e         ?U = =495 kJ mol-1

Cl + e- 2118_First order reactions1.png Cl-              ?U = - 349 KJ mol-1

And thus,

Na = Cl 2118_First order reactions1.png Na+ + Cl-    ?U = + 146 KJ mol-1

Infinitely separated gas phase Na and Cl ions lie at an energy 147 KJ mol-1 higher than separateNa and Cl atoms.

As Na+ and Clions approach each other, the potential energy becomes more negative. If we treat the ions at point charges, this potential energy is given by the coulombic term:

Ucoul = - e2/ (4∏e0)/ r

Where r is the internuclear distance, a curve for this function, based on the energies of separateNa+ and Cl- ions has been added.

An opposing effect exists in the form of repulsion between the nuclei, each with its closed shell of electrons. This repulsion term cannot easily be deduced, and it is satisfactory here to use an empirical expression to represent the repulsion that sets in at small internuclear distances. The variation of this repulsive energy contribution with internuclear distance is satisfactorily represented by an empirical equation of the form:

Urep = be-r/p, where p and b are empirical constants.

Furthermore, to a quite good approximation, the constant p can be taken to be the same for all ionic molecules and equal to 0.30 × 10 -10 m = 30 pm. Thus,

Urep = be -r/(0.30 × 10-10)

The total potential energy can now be written as:

U = - e2/(4∏e0)/r + be -r/(0.30 × 10-10)


The value of the remaining empirical constant b can be deduced by requiring U to have a minimum at the experimentally determined equilibrium bond length. Setting the derivate equal to zero for r = 2.36 × 10-10 m, the equilibrium bond length for NaCl, gives b = 1.95 × 105 kJmol-1. Substitution of the numerical value e2/(4∏eo) and expressing r in picometers gives:

U(kJ mol-1) = - 138,900/r + 195,000e-r/30 (r in picometers)


Calculated dissociation energy = 514 - 146 = 368 KJ mol-1

The result can be compared with the experiment value of 406 kJ mol-1

The attraction energy curve, the repulsion energy curve, and the total energy curve are the ionic model describes the system satisfactorily up to an internuclear separation of about 100 pm. Then the bond description must changes so that at complete separation the products released from each other are atoms rather than ions. 

   Related Questions in Chemistry

  • Q : Benzoic acid is weaker than paranitro

    Briefly state that Benzoic acid is weaker than paranitro benzoic acid?

  • Q : Inorganic Chemistry Inorganic

    Inorganic Chemistry:In the year 1869, Russian Chemist Dmitry Mendeleyev forms the periodic table of the element. Since Newlands did before him in the year 1863, Mendeleyev categorizes the el

  • Q : Mole fraction of benzene Choose the

    Choose the right answer from following. In a solution of 8.7g benzene C6H6 and 46.0 gm toluene ,(C6, H5, CH3) the mole fraction of benzene in this solution is: (a)1/6 (b)1/5 (c)1/2 (d)1/3

  • Q : Calculating total number of moles

    Choose the right answer from following. While 90 gm of water is mixed with 300 gm of acetic acid. The total number of moles will be: (a)5 (b)10 (c)15 (d)20

  • Q : Question based on relative lowering of

    Give me answer of this question. When a non-volatile solute is dissolved in a solvent, the relative lowering of vapour pressure is equal to: (a) Mole fraction of solute (b) Mole fraction of solvent (c) Concentration of the solute in grams per litre (d) Concentratio

  • Q : Thermodynamics 1 Lab Report I already

    I already did Materials and Methods section. I uploaded it with the instructions. Also, make sure to see Concept Questions and Thinking Ahead in the instructions that I uploaded. deadline is tomorow at 8 am

  • Q : Number of moles present in water

    Provide solution of this question. How many moles of water are present in 180 of water: (a)1 mole (b)18 mole (c)10 mole (d)100 mole

  • Q : Effect on vapour pressure of dissolving

    Give me answer of this question. When a substance is dissolved in a solvent the vapour pressure of the solvent is decreased. This results in: (a) An increase in the b.p. of the solution (b) A decrease in the b.p. of the solvent (c) The solution having a higher fr

  • Q : Problem on Osmotic Pressure of solution

    The osmotic pressure of a 5% solution of cane sugar at 150oC  is (mol. wt. of cane sugar = 342)(a) 4 atm (b) 3.4 atm (c) 5.07 atm (d) 2.45 atmAnswer: (c) Π = (5 x 0.0821 x 1000 x 423)/(342 x 100) = 5.07 atm

  • Q : Molar mass of solute The boiling point

    The boiling point of benzene is 353.23 K. If 1.80 gm of a non-volatile solute was dissolved in 90 gm of benzene, the boiling point is increased to 354.11 K. Then the molar mass of the solute is: (a) 5.8g mol-1  (b)