--%>

Explain alcohols and phenols in organic chemistry.

Alcohols and phenols are the compounds containing one or more hydroxyl groups (- OH). The alcohols contain the -OH group attached to alkyl group whereas in phenols, the -OH group is attached to aromatic ring. These are classified as mono-, di- and trihydric alcohols or phenols according to the number of -OH groups contained in their molecules. Some examples of mono-, di- and trihydric alcohols and phenols are as follows:

    Alcohols

2399_alcohol and phenol.png 

It may be noted that the aromatic compounds in which -OH group is not directly attached to benzene ring are not phenols but are called aromatic alcohols. These may also be called as aryl derivatives of aliphatic alcohols. When four or more hydroxyl groups are present, they are called polyhydric alcohols or polyhydric phenols.

Monohydric alcohols may be further classified according to the hybrid state of the carbon atom to which the -OH group is attached.
    
Compounds containing Csp3 ) -OH bond

In this type of alcohols, the -OH group is attached to a sp3 hybridised carbon atom. They are further classify as follows:

Primary (1°), secondary (2°) and tertiary (3°) alcohols

Monohydric alcohols are classified as primary, secondary or tertiary alcohols depending upon whether the hydroxyl group is attached to a primary, secondary or tertiary carbon atom. For instance,

1240_alcohol and phenol1.png 

Allylic alcohols: in allylic alcohols, the -OH group is attached to a sp3-hybridised carbon next to the carbon-carbon double bond, that is to an allylic carbon. For instance,

2066_alcohol and phenol2.png 

Benzylic alcohols: in benzlylic alcohols, the -OH group is attached to a sp3 -hybridised carbon atom next to an aromatic ring. Allylic and benzylic alcohols can be secondary, primary or tertiary.
    
Compounds containing Csp3 )-OH bond:

These alcohols include -OH group bonded to a carbon-carbon double bond i.e. to a vinylic carbon or to an aryl carbon. For example, vinylic alcohols and phenols belong to this class of compounds.

   Related Questions in Chemistry

  • Q : Molecular Diameters The excluded volume

    The excluded volume b, introduced by vander Wall's as an empirical correction term, can be related to the size gas molecules. To do so, we assume the excluded volume is the result of the pairwise coming together of molecules. This assumption is justified when b values

  • Q : Dipole attractions-London dispersion

    Describe how dipole attractions, London dispersion forces and the hydrogen bonding identical?

  • Q : Precipitation problem On passing H 2 S 

    On passing H2S  gas through a solution of Cu+ and Zn+2 ions, CuS is precipitated first because: (i) Solubility product of CuS is equal to the ionic product of ZnS (ii) Solubility product of CuS is equal to the solubility product o

  • Q : Hybridization Atomic orbitals can be

    Atomic orbitals can be combined, in a process called hybridization, to describe the bonding in polyatomic molecules. Descriptions of the bonding in CH4 can be used to illustrate the valence bond procedure. We must arrive a

  • Q : Polymers comparison of biodegradable

    comparison of biodegradable and non-biodegradable polymers

  • Q : Reason for medications contain hcl What

    What is the reason behind this that some medications contain hcl?

  • Q : Question based on relative lowering of

    Give me answer of this question. When a non-volatile solute is dissolved in a solvent, the relative lowering of vapour pressure is equal to: (a) Mole fraction of solute (b) Mole fraction of solvent (c) Concentration of the solute in grams per litre (d) Concentratio

  • Q : Freezing point of equimolal aqueous

    The freezing point of equi-molal aqueous solution will be maximum for:            (a) C6H5NH3+Cl-(aniline hydrochloride)  (b) Ca(NO3

  • Q : Molarity of cane sugar solution 171 g

    171 g of cane sugar (C12H22O11)  is dissolved in one litre of water. Find the molarity of the solution: (i) 2.0 M (ii) 1.0 M (iii) 0.5 M (iv) 0.25 M Choose the right answer from above.