Estimating solubility of oxygen in water
The Henry's law constant for oxygen in water is as follows: Temperature, °C 0 10K, mmHg/mol fraction 1.94 x 107 2.48 x 107Estimate the solubility of oxygen in water (in mg/L) at 20°C and a total air pressure of 1 atm.
The Henry's law constant for oxygen in water is as follows:
Temperature, °C 0 10K, mmHg/mol fraction 1.94 x 107 2.48 x 107Estimate the solubility of oxygen in water (in mg/L) at 20°C and a total air pressure of 1 atm.
A stream of steam at 15 bar and 300 oC is used to produce work using a steam turbine. a. Before the turbine, steam flows in a pipe (4 cm in diameter) at a mass flow rate of 3 g/s. Calculate the mean velocity in the pipe
I) Sulphur dioxide (SO2) with a volumetric flow rate 5000cm3/s at 1 bar and 1000C is mixed with a second SO2 stream flowing at 2500cm3/s at 2 bar and 200C. The process occurs at steady state. You may assume ideal gas behaviour. For SO2 take the heat capacity at constant pressure to be CP/R = 3.267+5
Natural Gas is flowing through a 10 inch schedule 40 pipe. The gas is at 109°F and 7.3 psig. The outside air temperature is 92°F. If the flow rate of the gas is 8,000 SCFM: What is the flow rate in lb/hr?
A steady-state flow process is used to heat methanol in a tank. The incoming stream is at 2 bar and 25 oC and has a flow rate of 5 kg/s. The outgoing stream is at 1 bar, 100 oC. Heating is provided by a heating coil immersed in a tank. Given the
I need to solve the material and energy balance for the att.
to determine the temperature that occurred in a fire in a warehouse, the arson investigator noticed that the relief valve on a methane storage tank had popped open at 3000 psig, the rated value. Before the fire started, the tank was presumably at ambient conditions and the gage read 1950 psig. If th
The Clausius-Clapeyron equation gives us an expression for dP/dT. Now we will derive an analog to the Clausius-Clapeyron equation by obtaining an expression for dT/dµ when two phases are at equilibrium. For simplicity, let’s derive this fo
Cumene is produced by the vapour phase reaction of benzene with propylene. The fresh feeds have the following compositions: Benzene: 99% w/w benzene, 1% w/w toluene Propylene: 98% v/v propylene,
Consider a chemical reaction: a CH3-CH=CH2 + b NH3 + c O2 → d CH2=CH-C≡N + e H2O 1. &
A stream of propane is throttled from 4.298 bar and 450 K to 0.22 bar. This process is irreversible due to frictional losses at the nozzle. a. In words or equations, why are frictional losses irreversible? Discover Q & A Leading Solution Library Avail More Than 1446991 Solved problems, classrooms assignments, textbook's solutions, for quick Downloads No hassle, Instant Access Start Discovering 18,76,764 1956425 Asked 3,689 Active Tutors 1446991 Questions Answered Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!! Submit Assignment
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