Dynamic model for the paper machine headbox
Explain and derive the Dynamic model for the paper machine headbox?
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We'll first develop a dynamic model for the paper machine headbox.A stock balance around the headbox. A suffix hb refers to the head box. Accumulation = Input – Outputdmhb/dt = ρqin – ρqoutNow ρ, is the stock density, but since the consistancy is 0.5% only, ρ = ρw = Water densityd(ρVhb)/dt = ρqin – ρqoutdVhb/dt = qin – qoutAhbdh/dt = qin – qoutwhere, Ahb, is the c/s area of header and assumed to be constant. qout, is the flow out of the header, and is only through slice, and can be written as, CAs(2gh)1/2, where As, is the cross sectional area of slice perpendicular to the flow, and C is characteristic constant coefficient for the slice.Hence, Ahbdh/dt = qin – CAs(2gh)1/2,To find, we can write Bernoulli's equation between Vacuum Degasser and Headbox. Suffix vd refers to vacuum degasser. Pvd/ρ + W = (Phb + ρgh)/ρ + V2/2 V = {2[Pvd - (Phb + ρgh)]/ρ + 2W}1/2 qin = AinV = Ain{2[Pvd - (Phb + ρgh)]/ρ + 2W}1/2Hence the dynamic model is, Ahbdh/dt = Ain{2[Pvd - (Phb + ρgh)]/ρ + 2W}1/2 – CAs(2gh)1/2,where the rate of stock height change in head box is related to the pressure in vacuum degasser and height. We have to linearize the non linear dynamic model. So that the effective model will be,τdh'/dt = KpP'hb + Khh',So as we see the the response of the height of stock to variations in vacuum degasser pressure is first order lag. We don't know the dynamics of level sensor or transmitter, but we'll assume it's also first order lag. Hence the effective system will be a second order. And hence it'll be oscillatory, and we propose the PID controller for level control by manipulating the speed of fan pump. Using MATLAB control toobox and given values of the parameters in the problem, we approximately find the following controller parameter settings. Kc = 9.6, τI = 2.3 min, τD = 3.5 min.Similarly, a propotional integral controller is proposed for pressure control in head box.The pressure in the head box is related to in flow of air, which is controlled by PI controller. The air is available at pressure of 300 kPa. dPhb/dt = f(Qin), where is the inlet flow rate of air. This will be pure capacitive system, hence we propose PI controller. We find the controller parameters for this, Kc = 14.5, τI = 4.5 min.
The approximate equation for the velocity distribution in a rectangular channel with the turbulent flow is Q : Problem related to mass flow rate Water Water flows via a control volume as illustrated in the figure below. At Section (1) the diameter is 40 mm and the velocity profile is given by the V(r) = 10 (4 – r2) m/s, here r is the distance from the centerline. At Section (2) the mass flow r
Water flows via a control volume as illustrated in the figure below. At Section (1) the diameter is 40 mm and the velocity profile is given by the V(r) = 10 (4 – r2) m/s, here r is the distance from the centerline. At Section (2) the mass flow r
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