--%>
Assignment Help - homework help

Direction of dipole moment expected for hydrogen bromide

Illustrate the direction of the dipole moment expected for hydrogen bromide?

E

Expert

Verified

An HBr molecule is linear (clearly, as it comprises two atoms only). The dipole moment is a vector, parallel to a bond, pointing to the partially positively charged atom, i.e., in this situation, hydrogen. Magnitude of the dipole moment is difference in the fractional electrical charges on every atom times the spatial separation of atoms in that bond. In a molecule with more than one bond (more than two atoms), the dipole moment of all bond must be added vectorially and the resulting vector will determine dipole moment of that molecule. For example, carbon dioxide contains two carbon-oxygen double bonds of high polarity, but because molecule is linear, and individual dipoles oppose each other, carbon dioxide molecule has no left dipole moment.

   Related Questions in Chemistry

  • Q : Solution problem What is the correct

    What is the correct answer. To made a solution of concentration of 0.03 g/ml of AgNO3, what quantity of AgNO3 must be added in 60 ml of solution: (a) 1.8  (b) 0.8  (c) 0.18  (d) None of these

    		•
  • Q : Dipole moment of chlorooctane

    Illustrate the dipole moment of chlorooctane?

    		•
  • Q : Neutralization of benzoic acid Choose

    Choose the right answer from following. How many grams of NaOH will be required to neutralize 12.2 grams of benzoic acid : (a) 40gms (b) 4gms (c)16gms (d)12.2gms

    		•
  • Q : Mole fraction of hydrogen Give me

    Give me answer of this question. In a mixture of 1 gm H2 and 8 gm O2 , the mole fraction of hydrogen is: (a) 0.667 (b) 0.5 (c) 0.33 (d) None of these

    		•
  • Q : Law of multiple proportions and Law of

    Describe the difference between law of multiple proportions and law of definite proportions?

    		•
  • Q : Define Bond Energies - Bond Charges

    Energy changes in some chemical reactions can be used to deduce the energies of chemical bonds. Our understanding of the molecular basis of thermodynamic properties is extended when we ask why the enthalpy change for a reaction is what it is. We deduce,

    		•
  • Q : Molarity of Nacl solution When 5.85 g

    When 5.85 g of NaCl (having molecular weight 58.5) is dissolved in water and the solution is prepared to 0.5 litres, the molarity of the solution is: (i) 0.2 (ii) 0.4 (iii) 1.0 (iv) 0.1

    		•
  • Q : Neutralization of sodium hydroxide How

    How much of NaOH is needed to neutralise 1500 cm3 of 0.1N HCl (given = At. wt. of Na =23): (i) 4 g  (ii) 6 g (iii) 40 g  (iv) 60 g

    		•
  • Q : Group IV Cations Chromium(III)

    Chromium(III) hydroxide is highly insoluble in distilled water but dissolves readily in either acidic or basic solution. Briefly explain why the compound can dissolve in acidic or in basic but not in neutral solution. Write appropriate equations to support your answer.

    		•
  • Q : Q what is the basicity of primary

    what is the basicity of primary secondary and tertiary amines in chlorobenzene

    		•