Dipole moment of chlorooctane
Illustrate the dipole moment of chlorooctane?
Expert
There are various forms of molecule "chlorooctane.". Because of the chlorine atom can be attached to an octane chain in many places, and all different placement will effect in a different dipole moment. If we specify a structure of the compound more precisely (1-chlorooctane or 2-chlorooctane for example), it can be determine its dipole moment.
Give me answer of this question. The vapour pressure of water at 20degreeC is 17.54 mm. When 20g of a non-ionic, substance is dissolved in 100g of water, the vapour pressure is lowered by 0.30 mm. What is the molecular weight of the substances: (a) 210.2 (b) 206.88
In Einstein’s mass energy relation e = mc2 for what is c employed or why is light needed for the reactions. As the reactions are with the help of neutrons?
Differentiate between the modern periodic table and Mendeleevs table?
Describe the various cons of eating the organic foods? Briefly illustrate it.
These are polymers that can be broken into small segments by enzyme-catalysed reactions. The required enzymes are produced by microorganism. It is a known fact that the carbon-carbon bonds of chain growth polymers are inert to enzyme-catalysed reactions, and hence they are non biod
Provide solution of this question. While 1.80gm glucose dissolve in 90 of H2O , the mole fraction of glucose is: (a) 0.00399 (b) 0.00199 (c) 0.0199 (d) 0.998
Briefly describe the procedure for separating the components of the gun-powder?
what is molarity of a solution of hcl which contains 49% by weight of solute and whose specific gravity is 1.41
Choose the right answer from following. When 6gm urea dissolve in180gm H2O . The mole fraction of urea is : (a)10/ 10.1 (b)10.1/10 (c)10.1/ 0.1 (d) 0.1/ 10.1
Give me answer of this question. The number of moles of solute per kg of a solvent is called its: (a) Molarity (b) Normality (c) Molar fraction (d) Molality
18,76,764
1955499 Asked
3,689
Active Tutors
1445496
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!