Dipole moment of chloro-octane
Describe the dipole moment of chloro-octane in brief?
Expert
There are manifold forms of the molecule ‘chloro-octane’. This is as the chlorine atom can be joined to the octane chain in many different places, and each and every distinct placement will outcome in a different dipole moment.
Illustrate a tripod? And how it’s used?
Help me to solve this question. Which of the following is incorrect: (a) Relative lowering of vapour pressure is independent (b)The vapour pressure is a colligative property (c)Vapour pressure of a solution is lower than the vapour pressure of the solvent (d)The
Alcohols and phenols are the compounds
Which of the following solutions will have a lower vapour pressure and why? a) A 5% aqueous solution of cane sugar. b) A 5% aqueous solution of urea.
Select the right answer of the question. Equimolar solutions in the same solvent have : (a)Same boiling point but different freezing point (b) Same freezing point but different boiling poin (c)Same boiling and same freezing points (d) Different boiling and differe
An example illustrates the type of mechanism that can be written to explain the development of flash photolysis reactions. Often, as the reactions in the ozone layer of the earth's atmosphere, we are interested in the kinetic behavior of species that are not a
The French chemist Francois Marie Raoult (1886) carried out a series of experiments to study the vapour pressure of a number of binary solutions. On the basis of the results of the experiments, he proposed a generalization called Raoult's law which states that, <
arrange in decreasing order of basicity pi pyridine,pyridine,pyrrole, morphine
Give me answer of this question. When a non-volatile solute is dissolved in a solvent, the relative lowering of vapour pressure is equal to: (a) Mole fraction of solute (b) Mole fraction of solvent (c) Concentration of the solute in grams per litre
bif3 is ionic while other trihalides are covalent in nature
18,76,764
1935304 Asked
3,689
Active Tutors
1440806
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!