--%>

Describe Thermodynamics Properties

The free energy property leads to convenient expressions for the volume and pressure dependence of internal energy, enthalpy and the heat capacities.

All the properties of a chemical system, a sample of a substance, or a mixture of substances have some fixed, definite values when the state of the system is set by the selection of, for example, a temperature and a pressure.

The properties that we have been with have the symbols V, U, H, S and G. these properties are all interrelated, as you know by thinking of the defining equations such as H = U + PV and G = H - TS.

Suppose the state of the system is changed. The values of the properties of the system change. These property changes must be interrelated.

An example of Maxwell's equations: the dependence of free energy on pressure and that on temperature are given by the partial derivatives,

(∂G/∂P)T = V and (∂G/∂T)P = -S

Since the free energy is a property, the change in free energy will be the same regardless of the order of differentiation with respect to pressure and temperature. We can write

[∂/∂P (∂G/∂T)P]T = [(∂/∂T) (∂G/∂P)T]P

With the equations for the derivatives of G with respect to T and P, this gives us 

(∂S/∂P)T = -(∂V/∂T)P

This derivative relation, who in itself is not at all revealing, is useful in leading us to other relations that give us unexpected insights. It is one of the expressions known as Maxwell's equations.

Pressure and volume dependence of U: for any process, the change in the energy dU of the system is related to the change in the energies of the thermal and mechanical surroundings by

dU = -dUtherm - dU
mech

For a process in which only the mechanical energy is involved, dUmech = P dV. For a reversible process dUtherm = -T dS. By considering this special process we arrive at the relation

dU = T dS - P dV

For a given change in S and V, there will be a particular change in U. thus although we arrived by considering a particular process, it is generally applicable.

Division of equation by dP followed by specification of constant temperature gives

(∂U/∂P)T = T(∂S/∂P)T - P(∂V/∂P)T

The pressure dependence of internal energy on volume can be obtained first writing the relation

(∂U/∂P)T = (VU/∂T)T - (∂V/∂P)T

The corresponding dependence of internal energy on volume can be obtained first writing the relation

(∂U/∂V)T = (∂U/∂P)T (∂P/∂V)T = -(∂V/∂T)P (∂P/∂V)T - P(∂V/∂P)T (∂P/∂V)T

= - T(∂V/∂T)T (∂P/∂V)T - P

The (∂V/∂T) P term can be expressed from dV = (∂V/∂T) P dT + (∂V/∂T)T dP by specifying constant volume, and rearranging to

(∂V/∂T)= - (∂V/∂P)T (∂P/∂T)V    

Now the equation for (∂U/∂V)T becomes

(∂U/∂V)T = T(∂P/∂T)V - P

Energy of an ideal gas

The internal energy U of a sample of an ideal gas depends on only the temperature, not on the pressure or volume of the sample. This ideal was justified by the kinetic molecular theory. We can show that it holds without stepping out of classical thermodynamics.

We can use conformity to the equation PV = nRT as a definition of ideal gas behaviour. If this relation is used to evaluate the terms, we arrive at

(∂U/∂P)T = 0 and (UV/∂V)T = 0

Thus, without any stipulation other than PV = nRT, arrive at the conclusion that the internal energy of an ideal gas depends on only the temperature.

   Related Questions in Chemistry

  • Q : Help 1) Chromium(III) hydroxide is

    1) Chromium(III) hydroxide is highly insoluble in distilled water but dissolves readily in either acidic or basic solution. Briefly explain why the compound can dissolve in acidic or in basic but not in neutral solution. Write appropriate equations to support your answer. 2) Explain how dissolving t

  • Q : Degree of dissociation The degree of

    The degree of dissociation of Ca(No3)2 in a dilute aqueous solution containing 14g of the salt per 200g of water 100oc is 70 percent. If the vapor pressure of water at 100oc is 760 cm. Calculate the vapor pr

  • Q : Product of HCl Zn Illustrate  the

    Illustrate  the product of HCl Zn?

  • Q : Reason for medications contain hcl What

    What is the reason behind this that some medications contain hcl?

  • Q : Question based on lowest vapour pressure

    Give me answer of this question. Among the following substances the lowest vapour pressure is exerted by: (a) Water (b) Mercury (c) Kerosene (d) Rectified spirit

  • Q : BASIC CHARACTER OF AMINES IN GAS PHASE,

    IN GAS PHASE, BASICITIES OF THE AMINES IS JUST OPPOSITE TO BASICITY OF AMINES IN AQEUOUS PHASE .. EXPLAIN

  • Q : Theory of one dimensional motion For

    For motion in one dimension, the distribution of the molecules over quantum states, speeds, and energies can be deduced.Here we show that the energy of a macroscopic gas sample can be described on the basis of our knowledge of the quantum states allowed to

  • Q : Explain the process of coagulation of

    Presence of small concentrations of appropriate electrolyte is necessary to stabilize the colloidal solutions. However, if the electrolytes are present in higher concentration, then the ions of the electrolyte neutralize the charge on the colloidal particles may unite

  • Q : Problem based on molarity Choose the

    Choose the right answer from following. The molarity of a solution of Na2CO3 having 10.6g/500ml of solution is : (a) 0.2M (b)2M (c)20M (d) 0.02M

  • Q : Liquid surfaces The surface between a

    The surface between a liquid and a vapour distinguishes these fluids. The surface tension of liquids can be looked upon as that the property which draws a liquid together and forms a liquid vapour interface, therefore, distinguishing liquids from gases.<