--%>

Describe Thermodynamics Properties

The free energy property leads to convenient expressions for the volume and pressure dependence of internal energy, enthalpy and the heat capacities.

All the properties of a chemical system, a sample of a substance, or a mixture of substances have some fixed, definite values when the state of the system is set by the selection of, for example, a temperature and a pressure.

The properties that we have been with have the symbols V, U, H, S and G. these properties are all interrelated, as you know by thinking of the defining equations such as H = U + PV and G = H - TS.

Suppose the state of the system is changed. The values of the properties of the system change. These property changes must be interrelated.

An example of Maxwell's equations: the dependence of free energy on pressure and that on temperature are given by the partial derivatives,

(∂G/∂P)T = V and (∂G/∂T)P = -S

Since the free energy is a property, the change in free energy will be the same regardless of the order of differentiation with respect to pressure and temperature. We can write

[∂/∂P (∂G/∂T)P]T = [(∂/∂T) (∂G/∂P)T]P

With the equations for the derivatives of G with respect to T and P, this gives us 

(∂S/∂P)T = -(∂V/∂T)P

This derivative relation, who in itself is not at all revealing, is useful in leading us to other relations that give us unexpected insights. It is one of the expressions known as Maxwell's equations.

Pressure and volume dependence of U: for any process, the change in the energy dU of the system is related to the change in the energies of the thermal and mechanical surroundings by

dU = -dUtherm - dU
mech

For a process in which only the mechanical energy is involved, dUmech = P dV. For a reversible process dUtherm = -T dS. By considering this special process we arrive at the relation

dU = T dS - P dV

For a given change in S and V, there will be a particular change in U. thus although we arrived by considering a particular process, it is generally applicable.

Division of equation by dP followed by specification of constant temperature gives

(∂U/∂P)T = T(∂S/∂P)T - P(∂V/∂P)T

The pressure dependence of internal energy on volume can be obtained first writing the relation

(∂U/∂P)T = (VU/∂T)T - (∂V/∂P)T

The corresponding dependence of internal energy on volume can be obtained first writing the relation

(∂U/∂V)T = (∂U/∂P)T (∂P/∂V)T = -(∂V/∂T)P (∂P/∂V)T - P(∂V/∂P)T (∂P/∂V)T

= - T(∂V/∂T)T (∂P/∂V)T - P

The (∂V/∂T) P term can be expressed from dV = (∂V/∂T) P dT + (∂V/∂T)T dP by specifying constant volume, and rearranging to

(∂V/∂T)= - (∂V/∂P)T (∂P/∂T)V    

Now the equation for (∂U/∂V)T becomes

(∂U/∂V)T = T(∂P/∂T)V - P

Energy of an ideal gas

The internal energy U of a sample of an ideal gas depends on only the temperature, not on the pressure or volume of the sample. This ideal was justified by the kinetic molecular theory. We can show that it holds without stepping out of classical thermodynamics.

We can use conformity to the equation PV = nRT as a definition of ideal gas behaviour. If this relation is used to evaluate the terms, we arrive at

(∂U/∂P)T = 0 and (UV/∂V)T = 0

Thus, without any stipulation other than PV = nRT, arrive at the conclusion that the internal energy of an ideal gas depends on only the temperature.

   Related Questions in Chemistry

  • Q : Product of HCl Zn Illustrate  the

    Illustrate  the product of HCl Zn?

  • Q : Strength of dilute acid of Sulfuric acid

    Select the right answer of the question.10ml of conc.H2SO4 (18 molar) is diluted to 1 litre. The approximate strength of dilute acid could be: (a)0.18 N (b)0.09 N (c) 0.36 N (d)1800 N

  • Q : What is covalent radii? Explain its

    Average covalent radii can be assigned on the basis of molecular structures. The accumulation of structural data by spectroscopic studies and both electron and x-ray diffraction studies allows one to investigate the possibili

  • Q : What is laser and explain its working?

    Laser action relies on a non-Boltzmann population inversion formed by the absorption of radiation and vibrational deactivation that forms a long lived excited electronic state. An excited state molecule can move to a lower energy state or return to the

  • Q : Problem on bubble point The following

    The following mixture of hydrocarbons is obtained as one stream in a petroleum refinery.

    Q : Question based on maximum vapour

    Provide solution of this question. Which has maximum vapour pressure: (a) HI (b) HBr (c) HCl (d) HF

  • Q : Describe chemical properties of amines.

    Like ammonia, primary, secondary and tertiary amines have a single pair of electrons on N atom. Hence chemical behavior of amines is similar to ammonia. Amines are basic in nature, and in most of the reactions they act as nucleophiles.      1. Reaction wi

  • Q : Relationship between Pressure and

    The pressure-temperature relation for solid-vapor or liquid vapor equilibrium is expressed by the Clausis-Clapeyron equation.We now obtain an expression for the pressure-temperature dependence of the state of equilibrium between two phases. To be specific,

  • Q : Describe Point Groups. For any

    For any symmetric object there is a set of symmetry operations that, together, constitute a mathematical group, called a point group.It is clear from the examples that most molecules have several elements of symmetry. The H2O

  • Q : Precipitation problem On passing H 2 S 

    On passing H2S  gas through a solution of Cu+ and Zn+2 ions, CuS is precipitated first because: (i) Solubility product of CuS is equal to the ionic product of ZnS (ii) Solubility product of CuS is equal to the solubility product o