--%>

What is Ideal Mixtures

Ideal mixing properties can be recognized in the formation of an ideal gas mixture from ideal gases.

Consider the formation of a mixture of gases i.e. a gaseous solution, from two mixtures of pure gases. A useful characterization of an ideal mixture, or solution, can be obtained by beginning with Dalton's law of partial pressures. That law, as seen in the pressure needed to confine a mixture of gases to a container is equal to the sum of the pressures that would be needed to confine the gas components separately to the same container.

The formation of Dalton's law binary mixture can be pictured by the process suggested in the fig. we begin with the gas sample containing of the separate components, each at pressure P. the mixing process consists of the expansion of each component to fill the entire container.

Suppose there are two containers nA mol of A and nB mol of B. the gas sample, both before and after mixing, has a volume V, and pressure to confine the gas to this volume is P. before mixing, the components are both occupy the total volume, and the pressures, or partial pressures, needed to confine them are also proportion to the number of moles. The relations that are implied are shown in fig.

The exponent of each component in this ideal gas mixture process occurs without regard to the presence of the other component. The change that occurs in the mixing is the sum of the changes experienced by each component.

From the relation between free energy and pressure for an ideal gas so that we have:

GA (in mixture) - GA (pure) = nRT in xB

G(in mixture) - GB (pure) = nRT in xB  


Ideal solutions: the free energy result of the above equation was developed by piecing together features of ideal behavior. In a more elegant procedure, adherence to the equation and to the consequences of this equation is used as the definition of ideal solution behavior. The entropy and free energy changes for the formation of 1 mol of an ideal gas solution are shown in the fig. and along with enthalpy it is accurate. Gas mixtures, except a high pressures or low temperatures, confirm to these ideal mixture characteristics. In what follows we treat gas mixtures as ideal.

Liquid mixtures, i.e. solutions, generally do not; behave according to these ideal mixing expressions. The volume of the solution is not always equal to the sum of the volume of the separate components. In the formation of a solution energy must often be exchanged with the thermal surroundings to maintain a constant temperature. Only for a few solutions are the free energy and entropy changes given by the ideal solution expressions. 

Entropy and free energy change at 25°C for formation of 1 mol of an ideal binary solution:

Mole fraction (xA) Mole fraction (xB) xA R In xA, Jk-1mol-1 xB R In xB, Jk-1mol-1 ΔSmix, JK-1mol-1 T ΔSmix, J mol-1 ΔGmix, J mol-1
1 0 0 0 0 0 -0
0.9 0.1 -0.79 -1.91 2.70 805 -805
0.8 0.2 -1.48 -2.68 4.16 1240 -1240
0.7 0.3 -2.08 -3.00 5.08 1510 -1510
0.6 0.4 -2.55 -3.05 5.60 1670 -1670
0.5 0.5 -2.88 -2.88 5.76 1720 -1720
0.4 0.6 -3.05 -2.55 5.60 1670 -1670
0.3 0.7 -3.00 -2.08 5.08 1510 -1510
0.2 0.8 -2.68 -1.48 4.16 1240 -1240
0.1 0.9 -1.91 -0.79 2.70 805 -805
0 0 0 0 0 0 -0

   Related Questions in Chemistry

  • Q : What are various structure based

    This classification of polymers is based upon how the monomeric units are linked together. Based on their structure, the polymers are classified as: 1. Linear polymers: these are the polymers in which monomeric units are linked together to form long straight c

  • Q : Determining maximum Osmotic pressure

    Which of the following would have the maximum osmotic pressure (assume that all salts are 90% dissociated): (a) Decimolar aluminium sulphate (b) Decimolar barium chloride (c) Decimolar sodium sulphate (d) A solution obtained by mix

  • Q : Finding Molarity of final mixture Can

    Can someone help me in finding out the right answer. 25ml of 3.0 MHNO3 are mixed with 75ml of 4.0 MHNO3. If the volumes are adding up the molarnity of the final mixture would be: (a) 3.25M (b) 4.0M (c) 3.75M (d) 3.50M

  • Q : Problem based on molecular weight

    Select the right answer of the question. Molecular weight of urea is 60. A solution of urea containing 6g urea in one litre is : (a)1 molar (b)1.5 molar (c) 0.1 molar (d) 0.01 molar

  • Q : Molecular weight of substance The

    The boiling point of a solution of 0.11 gm of a substance in 15 gm of ether was found to be 0.1oC higher than that of the pure ether. The molecular weight of the substance will be (Kb = 2.16)       (a) 148 &nbs

  • Q : Problem associated to vapour pressure

    Provide solution of this question. 60 gm of Urea (Mol. wt 60) was dissolved in 9.9 moles, of water. If the vapour pressure of pure water is P0 , the vapour pressure of solution is:(a) 0.10P0 (b) 1.10P0 (c) 0.90P0 (d) 0.99P0

  • Q : How to test a gas to see if it was

    Write a short note to describe how to test a gas to see if it was hydrogen or not?

  • Q : Group Cations Explain how dissolving

    Explain how dissolving the Group IV carbonate precipitate with 6M CH3COOH, followed by the addition of extra acetic acid, establishes a buffer with a pH of approximately

  • Q : Avogadros hypothesis how avogadros

    how avogadros hypothesis used to deduce the atomicity of elementry gases ?

  • Q : What is protein in Chemistry Illustrate

    Illustrate what is protein in Chemistry?