--%>
Assignment Help - homework help

Calculate the p- value

Medical tests were conducted to learn about drug-resistant tuberculosis. Of 284 cases tested in New Jersey, 18 were found to be drug- resistant. Of 536 cases tested in Texas, 10 were found to be drugresistant. Do these data indicate that New Jersey has a statistically significant higher outbreak of drugresistant tuberculosis cases? Use a .03 level of significance. What is the p- value, and what is your conclusion? Is the conclusion any different under critical-value approach?

E

Expert

Verified

Data

Let P1' denote observed proportion of drug resistant TB in New Jersey population and P2' is observed proportion of drug resistant TB in Texas, then

P1'= 18/284   = 0.0633803

P2' = 10/536  = 0.0186567

Hypothesis Formation

Null Hypothesis H0:    P1 - P2 = 0

Alternative Hypothesis H1:    P1 - P2 > 0

Z Statistic

Z = (P1' - P2')/SQRT(P(1-P)/(1/n1+1/n2))

Where P = (18+10)/(284+536)

                 = 0.0341463

Critical Region

Reject null hypothesis in favor of alternative if Z is greater than Z critical value of 1.88

Computation

Z = (0.0633803 - 0.0186567)/SQRT(0.0341463*(1-0. 0.0341463)(1/284+1/536))

   = 0.0447236/SQRT(0.0329803*0.0053868)

   = 0.0447236/SQRT(0.0001777)

   = 0.0447236/0.01333

   = 3.36

Decision

Null hypothesis is rejected in favor of alternative as Z value is greater than Z critical value. So we can say that New Jersey has statistically greater outbreak of drug resistant TB.

   Related Questions in Basic Statistics

  • Q : Data Description 1. If the mean number

    1. If the mean number of hours of television watched by teenagers per week is 12 with a standard deviation of 2 hours, what proportion of teenagers watch 16 to 18 hours of TV a week? (Assume a normal distribution.) A. 2.1% B. 4.5% C. 0.3% D. 4.2% 2. The probability of an offender having a s

    		•
  • Q : MANOVA and Reflection Activity

    Activity 10:   MANOVA and Reflection   4Comparison of Multiple Outcome Variables This activity introduces you to a very common technique - MANOVA. MANOVA is simply an extension of an ANOV

    		•
  • Q : Compare the test results The grade

    The grade point averages of 61 students who completed a college course in financial accounting have a standard deviation of .790. The grade point averages of 17 students who dropped out of the same course have a standard deviation of .940. Do the data indicate a

    		•
  • Q : Assumptions in Queuing system

    Assumptions in Queuing system: • Flow balance implies that the number of arrivals in an observation period is equal to the

    		•
  • Q : Computers playing games How Computers

    How Computers playing games can be categorized according to different dimensions?

    		•
  • Q : Statics for each of the following

    for each of the following studies a and b decide whether to reject the null hypothesis that groiups come from identical populations. Use the .01 level. (c) Figure the effects size for each study. (d) ADVANCED TOPIC: Carry out an analysis of variance for study (a) using the strucurtal method.

    		•
  • Q : Problems on ANOVA We are going to

    We are going to simulate an experiment where we are trying to see whether any of the four automated systems (labeled A, B, C, and D) that we use to produce our root beer result in a different specific gravity than any of the other systems. For this example, we would l

    		•
  • Q : Define Operational Analysis

    Operational Analysis: • Analysis method based on the measurement of the operational characteristics of the system.

    Q : Designing a system What are the

    What are the questions that comes into mind when designing a system?

    		•
  • Q : Program Evaluation and Review

    Program Evaluation and Review Technique (PERT) A) Developed by US Navy and a consulting firm in 1958 for the Polaris submarine project. B) Technique as for CPM method, but acti

    		•